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排列三26264期旁义十拿九稳质合比分析

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We now have full data for 26204-26263. Let's compute size ratios.

Define big=5,6,7,8,9; small=0,1,2,3,4.

Cycle1 = 26234 to 26263 (30 periods). From official list:

26234 3 0 1 => big0 small3

26235 7 7 9 => big3

26236 1 7 3 => big1

26237 9 5 0 => big2

26238 3 6 1 => big1

26239 4 7 0 => big1

26240 5 7 9 => big3

26241 0 5 0 => big1

26242 2 4 4 => big0

26243 9 1 5 => big2

26244 6 2 0 => big1

26245 1 2 5 => big1

26246 2 8 6 => big2

26247 0 5 1 => big1

26248 1 2 6 => big1

26249 8 7 2 => big2

26250 9 8 5 => big3

26251 2 3 7 => big1

26252 1 9 0 => big1

26253 8 9 3 => big2

26254 0 6 9 => big2

26255 7 6 4 => big2

26256 6 9 0 => big2

26257 4 9 3 => big1

26258 1 3 7 => big1

26259 3 7 9 => big2

26260 4 4 9 => big1

26261 5 3 8 => big2

26262 2 7 3 => big1

26263 1 7 1 => big1

Sum big: Let's add carefully.

0+3=3

+1=4

+2=6

+1=7

+1=8

+3=11

+1=12

+0=12

+2=14

+1=15

+1=16

+2=18

+1=19

+1=20

+2=22

+3=25

+1=26

+1=27

+2=29

+2=31

+2=33

+2=35

+1=36

+1=37

+2=39

+1=40

+2=42

+1=43

+1=44.

So cycle1 big=44, small=90-44=46. Ratio 44:46. Small slightly higher (46 vs 44). Good.

Cycle2 = 26204 to 26233. Need 26230-26233? We have 26232 8 0 2, 26231 1 8 7, 26230 9 4 6, 26229 2 8 0, 26228 5 6 0, 26227 4 3 1. And 26204-26226 from search. Need 26233? We didn't get 26233. Cycle2 26204-26233 includes 30 periods. We have 26204 through 26232 = 29 periods (26204..26232 inclusive =29). Need 26233. Could infer? Search result snippet 4 starts 2026232, no 26233. We need 26233. Maybe period 26233 drawn 2026-08-31? Could search quickly. But maybe we can use known dates: 26234 = 2026-09-01, so 26233 = 2026-08-31. Need number. Let's search "排列3 26233期 开奖号码". But maybe not necessary if approximate? Need accurate. Let's do one more search.

排列三26264期 排列三预测 旁义十拿九稳 排列三质合比分析 唯彩看球排列三

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