排列三26293期排列三遗漏数据组选分析

我无法从500彩票网直接抓到完整的号码遗漏表。模板小码/大码字段要求：出现次数、历史最大遗漏、当前遗漏、欲出几率。小码0-4，大码5-9.

I can derive current omission after 26292 using provided last 20:

Digits appearances, last occurrence position in chronological order. Let's list draws chronological from 26273 to26292:

26273: 7,0,3

26274: 3,6,1

26275: 2,0,6

26276: 9,0,6

26277: 2,7,8

26278: 5,8,3

26279: 4,7,1

26280: 8,6,4

26281: 9,8,3

26282: 6,4,7

26283: 2,5,8

26284: 6,7,7

26285: 6,1,3

26286: 2,1,8

26287: 1,5,4

26288: 4,1,5

26289: 2,9,9

26290: 0,3,9

26291: 2,7,6

26292: 4,4,6

We need current omission after26292. Calculate intervals backwards:

Digit 0: latest in26290. After that periods 26291,26292 = current omission2.

1: latest26288, then 26289,290,291,292 =4.

2: latest26291, after =1.

3: latest26290, after26291,292 =2.

4: latest26292, current0.

5: latest26288, after 26289,290,291,292=4.

6: latest26292, current0.

7: latest26291, after=1.

8: latest26286, after287,288,289,290,291,292=6.

9: latest26290, after291,292=2.

But template小码 ranking lists all 0-4 in ascending digit, not omission rank; each block 5 rows.大码 likewise. We can use current values above. Need occurrence counts historical total? Given sample values around 2000-2200. Since actual draws total ~26292 and digit appears each 3 digits, expected count ~7887? Wait sample at period2026247 shows count ~2000; that's likely not total across all draws? Wait排列三 started 2004, total periods ~? At 26247 maybe around? 2026 period 26247 (year 2026, 247th draw) total maybe ~5600 draws. Digit expected ~16800 appearances if counting digit occurrences across positions, but sample ~2000. Maybe "号码" means 组选 single digit frequency only counting whether appears in winning number, not across duplicates? At 5600 draws per draw, chance digit appears 1 - .9^3=.271, ~1518; sample ~2000 plausible. Great.

Need actual counts at current26293, can update sample counts from 2026247 by number of draws between? Given 26292 vs sample period26247 difference45 periods. Each digit's occurrence count based on appearance in draws (not duplicate count). We can calculate appearances over draws from 26248 to26292? But user only gives from26273. Not enough earlier 26248-26272. Could use counts ~ updated based on known sample. But exact likely not necessary? User says crawl official. Need maybe we can search specific digit omission values. Search exact 500 pages.